Java正则表达式将数字和字符串分开

Question

I have got strings like:

BLAH00001

DIK-11

DIK-2

MAN5

so all the strings are a kind of (sequence any characters)+(sequence of numbers)

and i want something like this:

1

11

2

5

in order to get those integer values, i wanted to separate the char sequence and the number sequence an do something like Integer.parseInt(number_sequence)

Is there something that does this job?

greetings

Answer 1

Try this:

public class Main {
    public static void main(String[]args) {
        String source = "BLAH00001\n" +
                "\n" +
                "DIK-11\n" +
                "\n" +
                "DIK-2\n" +
                "\n" +
                "MAN5";
        Matcher m = Pattern.compile("\\d+").matcher(source);
        while(m.find()) {
            int i = Integer.parseInt(m.group());
            System.out.println(i);
        }
    }
}

which produces:

1
11
2
5

Answer 2

String[] a ={"BLAH00001","DIK-11","DIK-2","MAN5"};
 for(String g:a)
  System.out.println(Integer.valueOf(g.split("^[A-Z]+\\-?")[1]));

 /*******************************  
   Regex Explanation :
     ^  --> StartWith
    [A-Z]+ --> 1 or more UpperCase
    \\-? --> 0 or 1 hyphen   
*********************************/

Answer 3

 Pattern p = Pattern.compile("^[^0-9]*([0-9]+)$");
 Matcher m = p.matcher("ASDFSA123");
 if (m.matches()) {
    resultInt = Integer.parseInt(m.group(1)));
 }

Answer 4

Maybe you want to have a look to Java Pattern and Matcher:

• http://download.oracle.com/javase/1.4.2/docs/api/java/util/regex/Pattern.html
• http://leepoint.net/notes-java/data/strings/40regular_expressions/26pattern-matcher.html
• http://answers.yahoo.com/question/index?qid=20071106173149AA4TUON