在Python中编写以空白分隔的文本是人类可读的

Question

I have a list of lists that looks something like this:

data = [['seq1', 'ACTAGACCCTAG'],
        ['sequence287653', 'ACTAGNACTGGG'],
        ['s9', 'ACTAGAAACTAG']]

I write the information to a file like this:

for i in data:
    for j in i:
        file.write('\t')
        file.write(j)
    file.write('\n')

The output looks like this:

seq1   ACTAGACCCTAG  
sequence287653   ACTAGNACTGGG  
s9   ACTAGAAACTAG  

The columns don't line up neatly because of variation in the length of the first element in each internal list. How can I write appropriate amounts of whitespace between the first and second elements to make the second column line up for human readability?

Answer 1

You need a format string:

for i,j in data:
    file.write('%-15s %s\n' % (i,j))

%-15s means left justify a 15-space field for a string. Here's the output:

seq1            ACTAGACCCTAG
sequence287653  ACTAGNACTGGG
s9              ACTAGAAACTAG

Answer 2

data = [['seq1', 'ACTAGACCCTAG'],
        ['sequence287653', 'ACTAGNACTGGG'],
        ['s9', 'ACTAGAAACTAG']]
with open('myfile.txt', 'w') as file:
    file.write('\n'.join('%-15s %s' % (i,j) for i,j in data) )

for me is even clearer than expression with loop

Answer 3

"%10s" % obj will ensure minimum 10 spaces with the string representation of obj aligned on the right.

"%-10s" % obj does the same, but aligns to the left.