有人可以解释以下奇怪的函数声明吗？

Question

std::thread f()
{
  void some_function(); // <- here
  return std::thread(some_function);
}

std::thread g()
{
  void some_other_function(int); // <- here
  std::thread t(some_other_function,42);
  return t;
}

Answer 1

Lines like:

void some_function();

simply declare a function which will be defined later. Functions don't necessarily have to be declared outside of function scope.

Answer 2

It's just a function declaration, as you thought. It is common (and recommended) to put function declarations in header files, but this is by no means required. They may be in function bodies.

Answer 3

Define a function returning a thread object:

std::thread f()
{

Declare an extern function with no arguments returning void (usually this is not done in local scope, but it is valid):

void some_function();

Start a thread executing that function, and return a handle to it:

return std::thread(some_function);
}

Same deal as before:

std::thread g()
{
void some_other_function(int);

But this is not valid. You can't make a copy of a thread, so technically it is not OK to make a local thread object and then return it. I'd be surprised if this compiled, but if it does, it might break when you build for the debugger.

std::thread t(some_other_function,42);
return t;
}

This would work, though:

return std::move( t );