如果直接或间接地从另一个方法调用某个方法，如何在Eclipse中查找？

Question

How to find out in Eclipse if certain method is potentially invoked or reachable (directly or indirectly) from another method?

Assume I want to refactor A.one() which can be negatively influenced by a side-effect in D.four() . Therefore I'd like to find out if D.four() can potentially be invoked from A.one() . I can see which methods are called from A.one() using the Call Hierarchy. I can navigate the call tree and eventually find that A.one() calls B.two() which calls C.three() which calls D.four() .

Is there a way in Eclipse to make this search somehow automatic?

ps. There's a "Filters..." option in Call Hierarchy Dialog, but it only hides matching names.

Answer 1

This is a modified version of the way you (@lexicore) found, that involves significantly less button punching (my changes in bold ):

• Open Call Hierarchy for A.one(), Show Callee Hierarchy.
• Select the root node, and press the * key until the whole tree is expanded. Note that you only need to press * on the root node. This will expand the whole tree in "no time".
• Right mouse click, Copy Expanded Hierarchy.
• Paste into a text file.
• Full-text search for D.four().

Notes

• The key * expands all unexpanded leaf nodes one level.
• The keys + and - works for expanding and closing just the selected node.
• I've tried this on a Swedish keyboard, where * is located in a different place than on a US keyboard, but hopefully Eclipse won't care about that.

Update

Here is some documentation , where the * key is mentioned.

Answer 2

We've just encountered a way. Not really "automatic", involves a lot of -> -button punching. :)

• Open Call Hierarchy for A.one() , Show Callee Hierarchy.
• Start from the root, expand the whole tree by clicking the -> button many many times. Really many times. :)
• Right mouse click, Copy Expanded Hierarchy.
• Paste into a text file.
• Full-text search for D.four() .

I hope there are better ways not involving punching the -> -button.

Answer 3

我所知道的最简单的方法是手动导航到D.four() ，在该方法上使用Call Hierarchy ，看看A.one()是否包含在层次结构中。