[英]Math.max seems to be returning the wrong answer
I have a list of double values that I don't know the range of and I want to find the maximum value. 我有一个双值列表,我不知道其范围,我想找到最大值。 However, the Math.max function is giving a curious result for this sample code: 但是,Math.max函数为此示例代码提供了一个奇怪的结果:
double a = -100.0;
double maxA = Double.MIN_VALUE;
maxA = Math.max(maxA, a);
System.out.println(maxA);
And the output is: 输出是:
4.9E-324
So for some reason, Double.MIN_VALUE is being considered the max when compared to -100.0. 因此,出于某种原因,与-100.0相比,Double.MIN_VALUE被认为是最大值。
Why? 为什么?
很明显-100小于4.9E-324
-100 , -99 ..... -1 , 0 , 4.9E-324 , 1 , 2 , 3......
MIN_VALUE A constant holding the smallest positive nonzero value of type double. MIN_VALUE一个常量,保持double类型的最小正非零值。
Note "positive" value. 注意“正面”值。
You are comparing it with a negative value is 1 > -1. 您将它与负值进行比较是1> -1。
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