PHP 日期； 如何找到下一年？

Question

I want to get today's date + one year. How do I achieve this with PHP's date functions?

Answer 1

echo date('Y', strtotime('+1 year'));

Answer 2

You can use strtotime and date

$date = '2010-09-16';
echo date('Y-m-d', strtotime("+12 months $date"));
// 2011-09-16

_{On a sidenote: DateTime questions like this have been answered over and over again, so you could have found how to add to a date easily by using the search function .}

Answer 3

From PHP's documentation :

<?php
    $date = new DateTime($your_supposed_date);
    $date->add(new DateInterval('P1Y'));
    echo $date->format('Y-m-d') . "\n";
?>

Gordon's much cleaner version (Thank you!):

<?php
    $date = new DateTime("+12 months $theDate");
    echo $date->format('Y-m-d') . "\n";
?>

Answer 4

$Ad_year = 2015-10-20
<?php echo $Ad_year + 1?>
Result 2016

Answer 5

You could use the new Datetime and Datetime_Intervall-classes introduced in the later PHP 5-versions.

I once posted an answer in this question . Maybe it helps you :)

The advantage is, that this classes also checks for leap-seconds and leap-years, timezones, etc.

Answer 6

如果您正在处理时间戳

echo time()+60*60*24*365

Answer 7

最短版本：

echo (int)date('Y') + 1;

Answer 8

最佳且简单的解决方案...您可以更改月份、年份或日期。

date('Y-m-d',strtotime("+1 day +2months +1 year"));

Answer 9

Below code also return next year from current date:

<?php echo date('Y', strtotime('+12 month'));>