在模式上分割字符串

Question

   var a="##55##data1!!##66##data4545!!##77##data44!!";

how to remove ##664545##data!! from the string

Edit:if we know the start value in a string ie,##66## and the end value ie,!!

In the main string how to remove characters starting from the start pattern,data after the start pattern till the end pattern

      My expected output will be ##55##data1!##77##data44!!

Answer 1

Using javascript and regex -

a.replace(/##66##[a-zA-Z0-9]*!!/g,"") 

If you want to parameterize this then you can do as given below where start and end are your parameters-

    var a = "##55##data1!!##66##data4545!!##77##data44!!";
    var start = "##66##";
    var end = "!!";

    var re = new RegExp(start + "[a-zA-Z0-9]*" + end, "g");

    return a.replace(re,"");

Answer 2

正则表达式的方式，用全局标志g来捕获所有匹配项：

a.replace(/##66##data!!/g,"")