有周数如何计算一周的最后一天？

Question

我在MySQL中将周数和年份作为单独的字段，如何计算给定年份中星期的最后一天（星期日）？

Answer 1

SELECT STR_TO_DATE('201038 Sunday', '%X%V %W');

This gives you sunday of the current week (38/2010). I used sunday because the "last day" is not consistend. sometimes its sunday, sometimes saturday (week starts on monday)...