是否可以在屏幕上在C程序中输出某个内存地址的内容？

Question

For debugging reasons, how can one in a C program print some memory address?

For instance, how should I do to print the content of address 0x611268 in form of a 4 byte float?

I know I could use a debugger, but I mean, to print out in screen.

Answer 1

More correctly, printf("Value = %f\\n", *((float*)0x611268));

Of course this assumes the address you've given is in the address space of the process running the printf .

Answer 2

打印指针内容的正确格式说明符是“％p”：

fprintf(stderr, "myVar contains %p\n", (void*)myVar);

Answer 3

#include <stdio.h>

int main(void)
{
  // pointer to int (4bytes) that points to memory address 0x611268
  int* address = (int *)0x611268; 

  printf("Memory address is: 0x%x\n", address);

  // Note that this address should exist on your process' memory or 
  // the line below will cause a Segmentation Fault
  *address = 0xdead; //assign a value to that address

  printf("Content of that address is: 0x%x\n", *address);

  return 0;
}