[英]What's wrong with my variable?
I can do a print_r of an employee object that I'm trying to pass into another method in another class and get the following: 我可以为一个雇员对象做一个print_r,尝试将其传递给另一个类中的另一个方法并获取以下信息:
emp Object ( [db:emp:private] => PDO Object ( ) [salesId:emp:private] => )
When I attempt to pass this object, I get an undefined variable error message. 当我尝试传递此对象时,收到未定义的变量错误消息。 What am I doing wrong?
我究竟做错了什么? Is there a PHP function that I can use to test this somehow?
是否可以使用PHP函数以某种方式对其进行测试? This object works great anywhere else.
该对象在其他任何地方都适用。
This error occurs when you try and access a variable that has not been previously defined. 当您尝试访问以前未定义的变量时,会发生此错误。
$object = new stdClass();
// This will give an undefined variable notice
echo $object->my_value
To avoid this you need to assign something to it 为了避免这种情况,您需要为其分配一些内容
$object = new stdClass();
// Assign test to my_value, then echo it, will output: test
$object->my_value = "test";
echo $object->my_value;
You can check for the presence of a variable using isset()
您可以使用
isset()
检查变量是否存在
$object = new stdClass();
// Check if my_value is set, if it is echo it
if(isset($object->my_value)) {
echo $object->my_value;
}
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