[英]How to replace all the characters with * using Regular Expression
I am having a text like我有一个像
s = bluesky
I want to get it as s = *******
(equal no of * as no of characters)我想把它作为s = *******
(等于没有 * 作为没有字符)
I am searching for a regular expression for Python.我正在寻找 Python 的正则表达式。
Edit 1 :编辑1:
b = '*'*len(s)
How can we do it in Django Template?我们如何在 Django 模板中做到这一点?
You don't need a regex for this:您不需要正则表达式:
s = 'bluesky'
b = '*'*len(s)
print b
output :输出:
>>> s = 'bluesky'
>>> b = '*'*len(s)
>>> print b
*******
No need for regexp, just text.replace('bluesky','*'*len('bluesky'))
不需要正则表达式,只需text.replace('bluesky','*'*len('bluesky'))
eg:例如:
>>> text = "s = bluesky"
>>> text.replace('bluesky','*'*len('bluesky'))
's = *******'
How can we do it in Django Template我们如何在 Django 模板中做到这一点
In a Django template?在 Django 模板中? Dead easy.容易死。
{% for char in s %}*{% endfor %}
Where s
is the template variable whose value is bluesky
.其中s
是模板变量,其值为bluesky
。
>>> import re
>>> re.sub("(\w+)\s*=\s*(\w+)", lambda m: "%s = %s" % (m.group(1), '*'*len(m.group(2))), "s = bluesky")
's = *******'
>>> re.sub("(\w+)\s*=\s*(\w+)", lambda m: "%s = %s" % (m.group(1), '*'*len(m.group(2))), "cat=dog")
'cat = ***'
Assuming your string is literally s = bluesky
假设你的字符串字面上是s = bluesky
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