正则表达式=>匹配Set中的所有内容，但一个字符除外

Question

假设我有一组字符[az]我想匹配集合中的每个字符，除了字符“a”谢谢！

Answer 1

[a-z-[e]]

means "any character between a and z except e". But as far as I know, only .NET, JGSoft and XML Schema support these " subtracted character classes ".

Another example:

[a-z-[aeiou]]

matches any (ASCII) consonant.

Answer 2

You can specify the character ranges as you want, for example:

[b-z]

This will only match the character from b to z . The only restriction is that it's a valid character range according to the character set that is used so that the first character has a lower code point than the second character.

Answer 3

Complete solution (ie no matter where the character is located in the [az] set and much more compatible):

[^\W\dA-Z && x]

Where "x" is the character (or group of characters, eg efgh) you want to exclude.

Tested on:

http://www.regexplanet.com/advanced/java/index.html

http://regexpal.com/