[英]Floating point and integer ambiguity
I have a function (and a constructor) that should be able to take integer and floating point values. 我有一个函数(和一个构造函数),应该能够取整数和浮点值。 In fact I want it to take an int64_t
or a long double
, so what I want is, 实际上我希望它采用int64_t
或long double
,所以我想要的是,
class Foo {
public:
Foo(int64_t value=0);
Foo(long double value);
};
However if I do this and try Foo f = 1;
但是,如果我这样做并尝试Foo f = 1;
the compiler complains about the conversion from int
to Foo
being ambiguous. 编译器抱怨从int
到Foo
的转换是模糊的。 Ok, but if I change the first constructor to take a int32_t
there is no such ambiguity. 好的,但是如果我改变第一个构造函数来获取int32_t
就没有这种歧义。 Can anyone explain to me why this is the case. 任何人都可以向我解释为什么会这样。
The type of the 1 literal is int. 1文字的类型是int。 Either constructor is going to need a conversion, int to int64_t vs int to long double. 构造函数都需要转换,int到int64_t vs int到long double。 The compiler doesn't think either of them is preferable so it complains. 编译器认为它们中的任何一个都不是优选的,所以它会抱怨。 Solve it by adding a Foo(int) constructor. 通过添加Foo(int)构造函数来解决它。 Or casting the literal, like (int64_t)1. 或者转换文字,如(int64_t)1。
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