如何在bash中列出所有不带扩展名的唯一文件名？

Question

I have a task where I need to move a bunch of files from one directory to another. I need move all files with the same file name (ie blah.pdf, blah.txt, blah.html, etc...) at the same time, and I can move a set of these every four minutes. I had a short bash script to just move a single file at a time at these intervals, but the new name requirement is throwing me off.

My old script is:
find ./ -maxdepth 1 -type f | while read line; do mv "$line" ~/target_dir/; echo "$line"; sleep 240; done

For the new script, I basically just need to replace find ./ -maxdepth 1 -type f with a list of unique file names without their extensions. I can then just replace do mv "$line" ~/target_dir/; with do mv "$line*" ~/target_dir/; .

So, with all of that said. What's a good way to get a unique list of files without their file names with bash script? I was thinking about using a regex to grab file names and then throwing them in a hash to get uniqueness, but I'm hoping there's an easier/better/quicker way. Ideas?

Answer 1

A weird-named files tolerant one-liner could be:

find . -maxdepth 1 -type f -and -iname 'blah*' -print0 | xargs -0 -I {} mv {} ~/target/dir

If the files can start with multiple prefixes, you can use logic operators in find. For example, to move blah.* and foo.*, use:

find . -maxdepth 1 -type f -and \( -iname 'blah.*' -or -iname 'foo.*' \) -print0 | xargs -0 -I {} mv {} ~/target/dir

EDIT

Updated after comment.

Here's how I'd do it:

find ./ -type f -printf '%f\n' | sed 's/\..*//' | sort | uniq | ( while read filename ; do find . -type f -iname "$filename"'*' -exec mv {} /dest/dir \; ; sleep 240; done )

Perhaps it needs some explaination:

• find ./ -type f -printf '%f\\n': find all files and print just their name, followed by a newline. If you don't want to look in subdirectories, this can be substituted by a simple ls ;
• sed 's/\\..*//' : strip the file extension by removing everything after the first dot. Both foo.tar ad foo.tar.gz are transformed into foo ;
• sort | unique sort | unique : sort the filenames just found and remove duplicates;
• ( : open a subshell:
  • while read filename : read a line and put it into the $filename variable;
  • find . -type f -iname "$filename"'*' -exec mv {} /dest/dir \\; : find in the current directory ( find . ) all the files ( -type f ) whose name starts with the value in filename ( -iname "$filename"'*' , this works also for files containing whitespaces in their name) and execute the mv command on each one ( -exec mv {} /dest/dir \\; )
  • sleep 240 : sleep
• ) : end of subshell.

Add -maxdepth 1 as argument to find as you see fit for your requirements.

Answer 2

Nevermind, I'm dumb. there's a uniq command. Duh. New working script is:

find ./ -maxdepth 1 -type f | sed -e 's/.[a-zA-Z]*$//' | uniq | while read line; do mv "$line*" ~/target_dir/; echo "$line"; sleep 240; done

EDIT: Forgot close tag on code and a backslash.