如何在C＃中将int转换为两个字节？

Question

如何在C＃中将int转换为两个字节？

Answer 1

Assuming you just want the low bytes:

byte b0 = (byte)i,
     b1 = (byte)(i>>8);

However, since 'int' is 'Int32' that leaves 2 more bytes uncaptured.

Answer 2

You can use BitConverter.GetBytes to get the bytes comprising an Int32. There will be 4 bytes in the result, however, not 2.

Answer 3

Another way to do it, although not as slick as other methods:

Int32 i = 38633;
byte b0 = (byte)(i % 256);
byte b1 = (byte)(i / 256);

Answer 4

Is it an int16?

Int16 i = 7;
byte[] ba = BitConverter.GetBytes(i);

This will only have two bytes in it.

Answer 5

Option 1:

byte[] buffer = BitConverter.GetBytes(number);

Option 2:

byte[] buffer = new byte[2];

buffer[0] = (byte) number;
buffer[1] = (byte)(number >> 8);

I prefer option 1!