在wicket中，如何从面板中的ajax组件的onSubmit刷新反馈面板？

Question

I have a feedback panel at the top of my page.

I have a number of panels, each have sub panels with AjaxFallback links that, when clicked I want to set info() messages to be displayed in the feedback panel.

Do I have to pass my feedback panel down through the layers of panels in order that I can re-add it to the Ajax target when the link is clicked? Or is there another way?

Thanks, Tom

Answer 1

以下在Wicket 6中有效

    target.addChildren(getPage(), FeedbackPanel.class);

Answer 2

Something has to add it to the target, but there are ways of using indirection so that things don't need to be passed around as much. See this blog article for one tactic.

Something similar is being added in Wicket 1.5. See WICKET-1312 for bug-tracking about this addition.