如何使用$ .getJSON从php文件中的JSON数据？
[英]How to JSON data using $.getJSON from a php file?
问题描述
I have a php file that receives data from mySQL table. 
我有一个php文件，可从mySQL表接收数据。 The mySQL table 'user_spec' has only one field 'options' that it returns. mySQL表“ user_spec”只有一个字段“选项”，它返回。 Then I convert returned data into JSON, under is code doing that. 然后，我将返回的数据转换为JSON，下面是执行此操作的代码。
<?php
$username = "user";
$password = "********";
$hostname = "localhost";
$dbh = mysql_connect($hostname, $username, $password) or die("Unable to connect
to MySQL"); //print "Connected to MySQL<br>";
$selected = mysql_select_db("spec",$dbh) or die("Could not select first_test");
$query = "SELECT * FROM user_spec";
$result=mysql_query($query);
echo json_encode(mysql_fetch_assoc($result));
?>
then in an HTML file, I try to output data by this piece of code But it is not working. 然后在HTML文件中，我尝试通过这段代码输出数据，但是它不起作用。 I will be very thankful for any help. 我将非常感谢您的帮助。
<html>
<head>
<script type="text/javascript"
src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script>
<script type="text/javascript" language="javascript">
function Preload() {
$.getJSON("Dhttp://localhost/conn_mysql.php", function(json){
alert("JSON Data: " + json.user_spec);
});}
</script></head>
<body onLoad="Preload()">
</body>
</html>
2 个解决方案
解决方案1
0 2010-10-19 09:39:30
- Jquery missing? jQuery不见了？ I assume you gave us a sample of your HTML file and that you have a reference to the jquery script on the page. 我假设您向我们提供了HTML文件的示例，并且您对页面上的jquery脚本有引用。
- Syntax error? 语法错误？ as Felix wrote - use console of firebug or similar to detect errors. 如Felix所写-使用Firebug控制台或类似控制台来检测错误。
- PHP error? PHP错误？ try to get the json response using a browser - see you got a response. 尝试使用浏览器获取json响应-看到响应。
- Address error? 地址错误？ try using absolute link instead of the relative link 尝试使用绝对链接而不是相对链接
Hope this gives you some options to narrow down the issue you arefacing. 希望这给您一些选择来缩小您所面临的问题的范围。
解决方案2
0 已采纳 2010-10-19 10:36:19
I think instead of using the file adress: "D:xampp/htdocs/conn_mysql.php" you must use an url defined by xampp such as "http://localhost/mytest/conn_mysql.php" 我认为，必须使用xampp定义的网址，例如“ http：//localhost/mytest/conn_mysql.php”，而不是使用文件地址“ D：xampp / htdocs / conn_mysql.php ”
Another thing you need to look out is the method. 您需要注意的另一件事是方法。 $.getJSON ( http://api.jquery.com/jQuery.getJSON/ ), as its name says, works with the GET method. 顾名思义 ， $ .getJSON （ http://api.jquery.com/jQuery.getJSON/ ）与GET方法一起使用。 Maybe you should try $.post or $.ajax ( http://api.jquery.com/jQuery.post/ ). 也许您应该尝试$ .post或$ .ajax （ http://api.jquery.com/jQuery.post/ ）。
Oh! 哦! And to start your script, not all the browsers supports the <body onload="">. 而且，要启动脚本，并非所有浏览器都支持<body onload =“”>。 Furthermore, it waits for the page to be loaded, not the DOM, what can give you problems with your scripts sometimes. 此外，它等待页面而不是DOM加载，这有时会给您脚本带来问题。 You should use $('document').ready(function() , that waits for the DOM to be loaded. This way: 您应该使用$（'document'）。ready（function（） ，它等待DOM加载。
<script type="text/javascript">
$('document').ready(function()
{
$.getJSON("D:xampp/htdocs/conn_mysql.php", function(json){
alert("JSON Data: " + json.options);
});
</script>
I hope it can be useful! 我希望它会有用！ ^^ ^^
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