Tomcat如何找到我的Web应用程序的主页？

Question

I am just getting started to learn about Web Apps and deploying them to Tomcat. So I started with a sample web app project - made up of struts, hibernate, etc., etc.

The ANT build was successful. Also, was able to deploy the web app through an xml under Catalina/host. I am able to open the web site with no issues.

This is the structure of my web app

 -exploded -WEB-INF -classes -lib -web.xml -index.jsp -welcome.html 

My question is

How does Tomcat know which is the first page / starting page / home page that it is supposed to open? Which file is this specified in?

Answer 1

In any web application, there will be a web.xml in the WEB-INF/ folder.

If you dont have one in your web app, as it seems to be the case in your folder structure, the default Tomcat web.xml is under TOMCAT_HOME/conf/web.xml

Either way, the relevant lines of the web.xml are

<welcome-file-list>
        <welcome-file>index.html</welcome-file>
        <welcome-file>index.htm</welcome-file>
        <welcome-file>index.jsp</welcome-file>
    </welcome-file-list>

so any file matching this pattern when found will be shown as the home page.

In Tomcat, a web.xml setting within your web app will override the default, if present.

Further Reading

How do I override the default home page loaded by Tomcat?

Answer 2

I already had index.html in the WebContent folder but it was not showing up , finally i added the following piece of code in my projects web.xml and it started showing up

  <servlet-mapping>
    <servlet-name>default</servlet-name>
    <url-pattern>/</url-pattern>
  </servlet-mapping>