的PHP / MySQL的帮助需要没有错误输出

Question

can some assist me with my code, everything looks correct checked each line at least 10 times. I've even hardcode in the user/pass for the query and still nothing.

<?php
include "database.php";

$sql = "SELECT UserName, Password, Language, Editor FROM admin_login WHERE UserName='".$_POST['username']."' AND Password='".$_POST['pwd']."'";

$result = @mysql_query($sql);
$line = @mysql_fetch_assoc($result);

    if (mysql_num_rows($result) == 0) {
#unsuccessful login
    header('Location: index.php' ); 
    } else {

#login successful, setting up session
    ob_clean();
session_start();
        $_SESSION['user'] = $line['UserName'];
        $_SESSION['pass'] = $line['Password'];
        $_SESSION['lang'] = $line['Language'];
        $_SESSION['editor'] = $line['Editor'];

#send to editor page        
            if ($_SESSION['lang'] == 'List') {
                header('Location: list.php');
                exit;

#send to announcer page   
            } else if ($_SESSION['lang'] == 'Order') {
                header('Location: order.php');
                exit;
            }
}
?>

Answer 1

从函数mysql_query和mysql_fetch_assoc中删除@，您将显示错误。

Answer 2

Some steps to follow:

1. Add MySQL error reporting such as (to the end of your SQL statement):

   or die ("Query failed: " . mysql_error() . " Actual query: " . $query)

2. Remove the @ symbols -- these suppress errors.

3. Run your query on the command line with your favorite SQL tool (phpMyAdmin, Navicat, Command line, etc) to see if it results in an error

Answer 3

Here's my version:

<?php

include 'database.php';

$sql = "SELECT `UserName`, `Password`, `Language`, `Editor` FROM `admin_login` WHERE `UserName` = '" . mysql_real_escape_string($_POST['username']) . "' AND `Password` = '" . mysql_real_escape_string($_POST['pwd']) . "' LIMIT 1;";

$result = mysql_query($sql);

if ($result === false)
{
    // Unsuccessful Login
    header('Location: index.php');
}

$user = mysql_fetch_assoc($result);

$_SESSION['user'] = $user;

if ($user['Language'] == 'List')
{
    header('Location: list.php');
    exit;
}
elseif ($user['Language'] == 'Order')
{
    header('Location: order.php');
    exit;
}

?>

If it still shows some errors copy/paste them here, if no errors are displayed and code still don't works then show us your database scheme and a database.php file.

Answer 4

As already stated, remove all the @ prefixes from functions. That suppresses all the errors.

Additionally, add the following two lines to the start of your script:

error_reporting(E_ALL);
ini_set('display_errors','1');

Answer 5

Your error report of PHP may be set to off. Please make it on or otherwise put ini_set('display_errors','1'); in the top of the php page where you are having this problem.