如何在长字符串中找到所有以'$'开头并以空格结尾的单词？

Question

在C＃中，如何使用正则表达式在长字符串中找到所有以'$'符号开头并以空格结尾的单词？

Answer 1

Try:

var matches = Regex.Matches(input, "(\\$\\w+) ");

In the above, \\\\w matches word characters. These are AZ, az, - and _ if I'm correct. If you want to match everything that's not a space, you can use \\\\S . If you want a specific set, specify this through eg [a-zA-Z0-9] .

The brackets around the (\\\\$\\\\w+) ensures that of a specific match, matches[0].Groups[1].Value; gives the value inside the backets (so, excluding the trailing space).

As a complete example:

string input = "$a1 $a2 $b1 $b2";

foreach (Match match in Regex.Matches(input, "(\\$\\w+) "))
{
    Console.WriteLine(match.Groups[1].Value);
}

This produces the following output:

$a1
$a2
$b1

The $b2 is of course omitted because it does not have a trailing space.

Answer 2

You may try it without regular expressions, that may be faster.

string longText = "";
    List<string> found = new List<string>();
    foreach (var item in longText.Split(' '))
    {
        if (item.StartsWith("$"))
        {
            found.Add(item);
        }
    }

EDIT: After Zain Shaikh's comment I've written a simple program to benchmark, here goes the results.

        string input = "$a1 $a2 $b1 $b2 $a2 $b1 $b2 $a2 $b1 $b2 $a2 $b1 $b2 $a2 $b1 $b2 $a2 $b1 $b2 $a2 $b1 $b2 $a2 $b1 $b2 $a2 $b1 $b2 $a2 $b1 $b2 $a2 $b1 $b2 $a2 $b1 $b2 $a2 $b1 $b2 $a2 $b1 $b2 $a2 $b1 $b2 $a2 $b1 $b2 $a2 $b1 $b2 $a2 $b1 $b2 $a2 $b1 $b2 $a2 $b1 $b2 $a2 $b1 $b2 $a2 $b1 $b2 $a2 $b1 $b2 $a2 $b1 $b2 $a2 $b1 $b2 $a2 $b1 $b2 $a2 $b1 $b2 $a2 $b1 $b2 $a2 $b1 $b2";
        var s1 = Stopwatch.StartNew();
        double first;
        foreach (Match match in Regex.Matches(input, "(\\$\\w+) "))
        {
        }
        s1.Stop();
        Console.WriteLine(" 1) " + (s1.Elapsed.TotalMilliseconds * 1000 * 1000).ToString("0.00 ns"));
        first = s1.Elapsed.TotalMilliseconds;
        s1.Reset();

        s1 = Stopwatch.StartNew();

        foreach (var item in input.Split(' '))
        {
            if (item.StartsWith("$"))
            {
            }
        }
        s1.Stop();
        Console.WriteLine(" 2) " + (s1.Elapsed.TotalMilliseconds * 1000 * 1000).ToString("0.00 ns"));
        Console.WriteLine(s1.Elapsed.TotalMilliseconds - first);

Output:

1) 730600.00 ns

2)  53000.00 ns

-0.6776

That means string functions (also with foreach) are faster than regular expression functions ;)

Answer 3

var a1 = "fdjksf $jgjkd $hfj".Split(" ".ToCharArray())
                                     .ToList()
                                     .Where(X=>Regex.Match(X , "(\\$[a-zA-Z]*)").Success);