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如何在C#中创建值生成器ala十六进制

[英]How to create value generator ala hex in c#

I would like to create unique value generator that would work like this: I have 8 places for chars and it would create values like this: 我想创建一个像这样工作的唯一值生成器:我有8个char位置,它将创建像这样的值:

00000001 . 00000001。 0000000z . 0000000z。 00000010 . 00000010。 0000001z 0000001z

etc. so it would create values from 00000001 to zzzzzzzz. 等等,因此它将创建从00000001到zzzzzzzz的值。

I have only 8 places because this is the size of the field in the database and I can't change it. 我只有8个地方,因为这是数据库中字段的大小,我无法更改。

Thanks in advance 提前致谢

使用bultin random()函数,然后在完成后将结果转换为十六进制。

Are you sure you're not looking for a GUID? 您确定不是要寻找GUID吗?

Same number of chars, different structure: 550e8400-e29b-41d4-a716-446655440000 You can create a new GUID: 字符数相同,结构不同:550e8400-e29b-41d4-a716-446655440000您可以创建一个新的GUID:

System.Guid.NewGuid().ToString(""N"")

Split it every 8 chars and append a dot, like this: 每8个字符将其拆分并添加一个点,如下所示:

string getUnique()
{
    char[] initial = System.Guid.NewGuid().ToString("N").ToCharArray();
    string result="";

    for(int i=0; i<initial.Count(); i++){
        result=result + initial[i];
        if((i+1)%4==0 && (i+1)!=initial.Count()){
            result = result + ".";
        }
    }
    return result;
}

something like this 像这样的东西

public class UniqueKeyMaker
{
    private int[] keys = new int[8];

    public void Reset()
    {
        for (int i = 0; i < keys.Length; i++)
            keys[i] = 0;
    }

    public string NextKey()
    {       
        string key = getCurrentKey();
        increment();
        return key;
    }

    private void increment()
    {
        int i = 7;
        while (keys[i] == 35)
        {
            keys[i] = 0;
            i--;
        }

        keys[i]++;
    }

    private string getCurrentKey()
    {
        StringBuilder sb = new StringBuilder();
        for (int i = 0; i < 8; i++)
        {
            if (keys[i] < 10)
                sb.Append((char)(keys[i] + (int)'0'));
            else
                sb.Append((char)(keys[i] - 10 + (int)'a'));
        }
        return sb.ToString();
    }
}

You just want to encode an int into a base 36 system. 您只想将int编码为base 36系统。 This might work like like following(probably has a few small mistakes since it's notepad code): 这可能像下面这样工作(由于它是记事本代码,可能有一些小错误):

string IntToID(long id)
{
    string result="";
    Contract.Require(id>=0);
    while(id>0)
    {
       int digit=id%36;
       char digitChar;
       if(digit<10)
         digitChar='0'+digit;
       else
         digitChar='a'+(digit-10);
       result+=digitChar;
       id/=36;
    }
    result=result.PadLeft('0',8);
    return result;
}

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