[英]If statement or while loop failing on me in php
I am fairly new to coding in php and have come accross a bit of a problem which I think is very simple. 我是一个相当新的PHP编码,并遇到了一个问题,我觉得很简单。 I am trying to capture the IP address of anybody that visits my website and stores that in my database. 我试图捕获访问我的网站并将其存储在我的数据库中的任何人的IP地址。 The code is as follows, I am not even sure the code will work but I do get the following error Parse error: syntax error, unexpected T_INC on line 29 which I will highlight in the code: 代码如下,我甚至不确定代码是否会工作,但我确实得到以下错误解析错误:语法错误,第29行意外的T_INC,我将在代码中突出显示:
$ip = $_SERVER['HTTP_CLIENT_IP'];
$query="SELECT * FROM ip";
$result = mysql_query($query);
$num = mysql_numrows($result);
$i = 1;
$found=false;
while(($i - 1) < $num){
$selection = mysql_query("SELECT ip FROM ip WHERE id=$i");
$tip = mysql_fetch_assoc($selection);
if($tip == $ip){
$found = true;
}
i++; //This is line 29
}
if($found == false){
$sql = "INSERT INTO `rowley_blog`.`ip` (`ip`) VALUES ('$ip');";
mysql_query($sql);
mysql_close();
}
您需要使用前缀变量$
,所以它的$i++
。
它应该是这样的:
$i++;
你需要在所有变量之前加上一个美元符号 - 应该是这样
$i++;
Apart from the syntax error: This code seems blown-up to me. 除了语法错误:这段代码似乎让我感到震惊。 Doesn't this do the same: 这不是一样的:
$ip = $_SERVER['HTTP_CLIENT_IP'];
mysql_query("REPLACE INTO `ip` (`ip`) VALUES ('" . mysql_real_escape_string($ip) . "')");
Remember: Good code is short code ;) 记住:好的代码是短代码;)
Furthermore: If you are only beginning to code PHP, please don't even start using the mysql_
extension. 此外:如果您只是开始编写PHP代码,请不要开始使用mysql_
扩展。 Instead use PDO : 而是使用PDO :
$ip = $_SERVER['HTTP_CLIENT_IP'];
$db->query("REPLACE INTO `ip` (`ip`) VALUES ('" .$db->quote($ip) . "')");
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.