[英]How to loop in bash script?
i have following lines in a bash script under Linux: 我在Linux下的bash脚本中有以下行:
...
mkdir max15
mkdir max14
mkdir max13
mkdir max12
mkdir max11
mkdir max10
...
how is the syntax for putting them in a loop, so that i don't have to write the numbers (15,14..) ? 如何将它们放在循环中的语法,以便我不必写数字(15,14 ..)?
with bash, no need to use external commands like seq
to generate numbers. 使用bash,无需使用
seq
等外部命令来生成数字。
for i in {15..10}
do
mkdir "max${i}"
done
or simply 或者干脆
mkdir max{01..15} #from 1 to 15
mkdir max{10..15} #from 10 to 15
say if your numbers are generated dynamically, you can use C style for loop 如果您的数字是动态生成的,您可以使用C样式进行循环
start=10
end=15
for((i=$start;i<=$end;i++))
do
mkdir "max${i}"
done
No loop needed for this task: 此任务不需要循环:
mkdir max{15..10} max0{9..0}
... but if you need a loop construct, you can use one of: ...但是如果你需要一个循环结构,你可以使用以下之一:
for i in $(seq [ <start> [ <step> ]] <stop>) ; do
# you can use $i here
done
or 要么
for i in {<start>..<stop>} ; do
# you can use $i here
done
or 要么
for (( i=<start> ; i < stop ; i++ )) ; do
# you can use $i here
done
or 要么
seq [ <start> [ <step> ]] <stop> | while read $i ; do
# you can use $i here
done
Note that this last one will not keep the value of $i outside of the loop, due to the |
请注意,由于
|
,最后一个不会将$ i的值保留在循环之外 that starts a sub-shell 这会启动一个子shell
for a in `seq 10 15`; do mkdir max${a}; done
seq
will generate numbers from 10
to 15
. seq
将生成10
到15
数字。
EDIT: I was used to this structure since many years. 编辑:多年来我习惯了这种结构。 However, when I observed the other answers, it is true, that the
{START..STOP}
is much better. 但是,当我观察到其他答案时,
{START..STOP}
确实更好。 Now I have to get used to create directories this much nicer way: mkdir max{10..15}
. 现在我必须习惯于以更好的方式创建目录:
mkdir max{10..15}
。
使用for循环
for i in {1..15} ; do
mkdir max$i
done
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