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WHERE子句中的SQL IN运算符

[英]SQL IN operator in the WHERE clause

The following query: 以下查询:

SELECT SUM (peak_power) FROM t_mpi_pv WHERE info_id IN ( 
 SELECT mp_info_id FROM t_mp WHERE mp_id IN (
  ARRAY[29800001,29800008,29800015,29800022,29800029]
 )
)

Doesn't work. 不行。 I get the error: 我收到错误:

"Operator does not exist: integer = integer[]". “运算符不存在:整数=整数[]”。

But

SELECT SUM (peak_power) FROM t_mpi_pv WHERE info_id IN ( 
 SELECT mp_info_id FROM t_mp WHERE mp_id = 29800001  
)

Works. 作品。

What am I doing wrong? 我究竟做错了什么?

Try: 尝试:

SELECT SUM (peak_power) FROM t_mpi_pv WHERE info_id IN ( 
 SELECT mp_info_id FROM t_mp WHERE mp_id IN 
  (29800001,29800008,29800015,29800022,29800029)
 )
)

Alternatively, use this syntax: 或者,使用以下语法:

SELECT  SUM(peak_power)
FROM    t_mpi_pv
WHERE   info_id IN
        (
        SELECT  mp_info_id
        FROM    t_mp
        WHERE   mp_id = ANY(ARRAY[29800001,29800008,29800015,29800022,29800029])
        )

Useful if you pass the array as a single bound variable or a parameter of a function: 如果将数组作为单个绑定变量或函数的参数传递,则非常有用:

CREATE FUNCTION fn_peak_power (mpids INT[])
AS
$$
        SELECT  SUM(peak_power)
        FROM    t_mpi_pv
        WHERE   info_id IN
                (
                SELECT  mp_info_id
                FROM    t_mp
                WHERE   mp_id = ANY($1)
                );
$$
LANGUAGE 'sql';

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