AWK输出到bash数组

Question

Im trying to put the contents of a simple command in to a bash array however im having a bit of trouble.

df -h | awk '{ print  $5" "$6 }'

gives percentage used in the file systems on my system output looks like this:

1% /dev
1% /dev/shm
1% /var/run
0% /var/lock
22% /boot
22% /home
22% /home/steve

I would then like to put each of these lines into a bash array array=$(df -h| awk '{ print $5 $6 }')

However when I print out the array I get the following:

5%
/
1%
/dev
1%
/dev/shm
1%
/var/run
0%
/var/lock
22%
/boot
22%
/home
22%
/home/steve

Bash is forming the array based on white spaces and not line breaks how can i fix this?

Answer 1

You need to reset the IFS variable (the delimeter used for arrays).

OIFS=$IFS #save original
IFS=','
df -h | awk '{ print $5" "$6"," }'

Answer 2

You could do this in Bash without awk.

array=()
while read -a line; do
    array+=("${line[4]} ${line[5]}")
done < <(df -h)

Answer 3

你可以用这个：

eval array=( $(df -h | awk '{ printf("\"%s %s\" ", $5, $6) }') )