C的赋值

Question

When you see code like this in C, what's the order of assignment?

int i = 0, var1, var2;

I don't understand the syntax...

Answer 1

Only i is assigned the value zero.

var1 and var2 are uninitialized.

Answer 2

There's no "assignment" in your code whatsoever. It is a declaration of three variables of type int , of which one is initialized with zero. The = symbol is an integral part of initialization syntax, it has nothing to do with any "assignment". And since there's only one initialization there, there's really no question about any "order".

If that doesn't answer your question, clarify it.

Answer 3

只有一个赋值（i = 0），其余的是定义。

Answer 4

i初始化为0而变量var1和var2未初始化，因此具有未指定的值（如果它们在本地范围中定义）。

Answer 5

所有这些都是局部变量，唯一的区别是我被赋值为零，而var1和var2的值是不可预测的，它们将具有垃圾值。