[英]calculate averages for 5 min intervals in mysql
I have a table log
with columns id
, myValue
, myCategory
and myTimestamp
.我有一个表
log
,其中包含id
、 myValue
、 myCategory
和myTimestamp
。 Suppose the table is filled like this:假设表格是这样填充的:
ID ![]() |
MYVALUE![]() |
MYCATEGORY![]() |
MYTIMESTAMP![]() |
---|---|---|---|
1 ![]() |
10 ![]() |
1 ![]() |
2010-11-1 10:00:00 ![]() |
2 ![]() |
20 ![]() |
1 ![]() |
2010-11-1 10:03:00 ![]() |
3 ![]() |
15 ![]() |
2 ![]() |
2010-11-1 10:15:00 ![]() |
4 ![]() |
05 ![]() |
2 ![]() |
2010-11-1 10:19:00 ![]() |
5 ![]() |
30 ![]() |
1 ![]() |
2010-11-1 10:24:00 ![]() |
6 ![]() |
12 ![]() |
1 ![]() |
2010-11-1 10:30:00 ![]() |
Now I would like to generate a table with an avg()
for column myValue
in 5 minute intervals for a specified myCheck
, starting from the last check entry.现在,我想为指定的
myCheck
以 5 分钟的间隔为列myValue
生成一个包含avg()
的表,从最后一个检查条目开始。
The output for myCheck = 1
should be like: myCheck = 1
的输出应如下所示:
ID ![]() |
AVERAGE![]() |
---|---|
1 ![]() |
12 ![]() |
2 ![]() |
30 ![]() |
3 ![]() |
15 ![]() |
The output for myCheck = 2
should be like: myCheck = 2
的输出应如下所示:
ID ![]() |
AVERAGE![]() |
---|---|
1 ![]() |
10 ![]() |
What is the best way to approach this?解决这个问题的最佳方法是什么? I have basic knowledge of MySQL but this puzzles me.
我对 MySQL 有基本的了解,但这让我很困惑。 Part of the query will be like this I suppose (without the 5 min interval grouping):
我想部分查询将是这样的(没有 5 分钟间隔分组):
SELECT
avg(myValue)
FROM
log
WHERE
myCheck = ..
How can I use the timestamps to generate 5 min intervals averages?如何使用时间戳生成 5 分钟间隔平均值? Any help is greatly appreciated.
任何帮助是极大的赞赏。
Maybe later but a shortest query would be:也许稍后,但最短的查询是:
SELECT ID, AVG(VALUE) as average, DATE_FORMAT(MIN(timestamp), '%Y-%m-%d %H:%i:00') AS tmstamp
FROM yourtable GROUP BY round(UNIX_TIMESTAMP(timestamp) DIV 60*5)
SELECT
DATE_FORMAT((atimestamp),
concat( '%Y-%m-%d %H:' ,
cast(round(minute(atimestamp)) - round(minute(atimestamp)) % 5 as char))
)AS rounded_time
,avg(price) , count(*) from table
This way you can get 5 , 10, 15, 30etc.这样你可以得到 5 , 10, 15, 30 等等。 minute average easily.
分钟平均很容易。
In case someone else is interested here is the answer I've come up with (with help from a colleague).如果其他人对此感兴趣,这是我想出的答案(在同事的帮助下)。
First create a stored procedure in MysQL like so (original source modified from here http://ondra.zizka.cz/stranky/programovani/sql/mysql_stored_procedures.texy ) :首先像这样在 Mysql 中创建一个存储过程(从这里修改的原始源http://ondra.zizka.cz/stranky/programovani/sql/mysql_stored_procedures.texy ):
DELIMITER $$
CREATE PROCEDURE generate_series (
iFrom TIMESTAMP, iTo TIMESTAMP, iStep INTEGER )
body:
BEGIN
DROP TEMPORARY TABLE IF EXISTS stamp_series;
CREATE TEMPORARY TABLE stamp_series ( stamp TIMESTAMP NOT NULL);
IF iFrom IS NULL OR iTo IS NULL OR iStep IS NULL
THEN LEAVE body; END IF;
SET @iMax = iFrom;
SET @iMin = iTo;
InsertLoop: LOOP
INSERT INTO stamp_series SET stamp = @iMax;
SET @iMax = DATE_SUB( @iMax, INTERVAL iStep SECOND);
IF @iMin > @iMax THEN LEAVE InsertLoop; END IF;
END LOOP;
END; $$
DELIMITER ;
then the actual query is like this:那么实际的查询是这样的:
CALL generate_series( timestamp1 , timestamp2 , 300);
SELECT stamp, DATE_SUB(stamp, INTERVAL 5 MINUTE) AS stamp_min_5, ( SELECT COALESCE( AVG(value), 0) FROM `table` WHERE `category` = 1 AND timestamp <= stamp AND timestamp > DATE_SUB(stamp, INTERVAL 5 MINUTE) ) AS gem FROM stamp_series;
Regards, Ivo问候,伊沃
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.