在bash中将一个字符串切成几行

Question

I want to take the path of the local directory and put each directory on the path in a different line. I've tried to do it using cut:

pwd | cut -f 1- -d\\/ --output-delimiter=\\n

but it doesn't change the '/'s into EOL, but puts n's instead. What am I doing wrong?

Answer 1

This should do the trick

pwd | tr '/' '\n'

If you don't want an empty line in the beginning (due to the initial / ) you could do

pwd | cut -b2- | tr '/' '\n'

Example:

#aioobe@r60:~/tmp/files$ pwd
/home/aioobe/tmp/files
#aioobe@r60:~/tmp/files$ pwd | cut -b2- | tr '/' '\n'
home
aioobe
tmp
files

Answer 2

你可以试试：

pwd | tr '/' '\n'

Answer 3

这就是你将如何完成你要做的事情（使用ANSI-C引用）：

pwd | cut -f 1- -d\/ --output-delimiter=$'\n'