将结构传递为C中的参数

Question

I am having this problem and Dont know the reason

I have this structure

typedef struct 
{

    Int32   frameID;
    Int32   slotIndx;
    Int32   symNumber;

}   recControlList;


    recControlList  *recControlListPtr;

Datatypes are typedefs.

Caller function is :

Fun( recControlListPtr);

Fun declaration is

Fun (recControlList *recControlListPtr);


syntax error : missing ')' before '*'

How to I pass structure as pointer into the function? Please help

Answer 1

You need to have the struct declaration and typedef before the declaration of Fun().

If all of this in the same file, then they are just in the wrong order. If the struct is declared in a different file, you need to #include that before the function prototype.

EDIT : So on your second question...

Answer 2

The declaration is missing a return type, eg:

void Fun (recControlList *recControlListPtr);

(edit: As pointed out by others, the return type in function declarations is optional in some variants of C, but it's good style and it can give you a better error message due to disambiguation).

Answer 3

You can refer http://fresh2refresh.com/c/c-passing-struct-to-function/ website. Very simple example program is given for Passing structures to function by address. I hope this will be useful for you.

Answer 4

You just pass it, such as in

char* xy = "HelloWorld";
if(!strcmp(xy, "HelloWorld"))

You can also do a

struct xy ;
functionName(&xy);

Did you specify a return value for your function?