仅从 DateTime 对象获取日期或时间

Question

I have a DateTime instance that has a Date and a Time. How do I extract only the date or only the time?

Answer 1

var day = value.Date; // a DateTime that will just be whole days
var time = value.TimeOfDay; // a TimeSpan that is the duration into the day

Answer 2

您还可以使用DateTime.Now.ToString("yyyy-MM-dd")作为日期，使用DateTime.Now.ToString("hh:mm:ss")作为时间。

Answer 3

You can use Instance.ToShortDateString() for the date,
and Instance.ToShortTimeString() for the time to get date and time from the same instance.

Answer 4

var currentDateTime = dateTime.Now();
var date=currentDateTime.Date;

Answer 5

With the .NET 6 which added DateOnly and TimeOnly structs it's now possible to get the date and time like this:

var dateTime = DateTime.Now;
var date = DateOnly.FromDateTime(dateTime);
var time = TimeOnly.FromDateTime(dateTime);

Docs:

• DateOnly
• TimeOnly

Answer 6

Sometimes you want to have your GridView as simple as:

  <asp:GridView ID="grid" runat="server" />

You don't want to specify any BoundField, you just want to bind your grid to DataReader. The following code helped me to format DateTime in this situation.

protected void Page_Load(object sender, EventArgs e)
{
  grid.RowDataBound += grid_RowDataBound;
  // Your DB access code here...
  // grid.DataSource = cmd.ExecuteReader(CommandBehavior.CloseConnection);
  // grid.DataBind();
}

void grid_RowDataBound(object sender, GridViewRowEventArgs e)
{
  if (e.Row.RowType != DataControlRowType.DataRow)
    return;
  var dt = (e.Row.DataItem as DbDataRecord).GetDateTime(4);
  e.Row.Cells[4].Text = dt.ToString("dd.MM.yyyy");
}

The results shown here.