我可以在大量HTML上使用PHP try / catch吗？

Question

I would like to surround this entire block of code in a try/catch since its causing an error when there is nothing in the grid array. Whats the best way to do this?

 <?php foreach ($grid->result() as $idx => $row): ?>  <?php if ($idx % 3 == 2): ?>
   <div class="img_grid_3"><img src="/images/thumb/<?= $row->images_name; ?>" /></div>
    <?php else: ?>
   <div class="img_grid"><img src="/images/thumb/<?= $row->images_name; ?>" /></div>
   <?php endif; ?>
<?php endforeach; ?>

Thanks

Answer 1

Maybe Im missing the point but why dont you test $grid before doing the foreach?

<?php if($grid): ?>
  .... foreach ....
<?php endif; ?>

Answer 2

If I got you right, you're looking for the @ error suppression operator. If you pass an empty array to foreach, you'll get a PHP warning, you can't catch this with a try/catch block.

<?php @foreach ($grid->result() as $idx => $row): ?>
   <?php if ($idx % 3 == 2): ?>
   <div class="img_grid_3"><img src="/images/thumb/<?= $row->images_name; ?>" /></div>
   <?php else: ?>
   <div class="img_grid"><img src="/images/thumb/<?= $row->images_name; ?>" /></div>
   <?php endif; ?>
<?php endforeach; ?>

It's possible to use a try catch block with html contents too, but it will obviously only catch Exceptions .

Note that it's cleaner to check wheter the array is empty or not before you use it in a foreach block.

Answer 3

foreach will not produce an error if the array is empty.

So either $grid is not an object, or result() is returning a non-array like false or null . If the former, surround the foreach with if ($grid) , of the latter, than use if (!empty($grid->result()))