在python中读取包含列表和逗号分隔的文件

Question

I have a file(.txt) which contains: [0 1,1 1,3 2,4 1]

I want to read the file in this way:

0 1 /n
1 1 /n
3 2 /n
4 1 /n

I have problem how to eliminate brackets and separate each line by comma. Thanks for your suggestions :)

Answer 1

>>> s = "[0 1,1 1,3 2,4 1]"
>>> print '\n'.join(s[1:-1].split(','))
0 1
1 1
3 2
4 1

Answer 2

A different method that will also work if the brackets are not the first and the last character:

print s[s.index("[")+1:s.index("]")].replace(",", "\n")

If the brackets always are the ifrst and the last character of the string, you can simplify this to

print s[1:-1].replace(",", "\n")

Answer 3

Simple snippet:

with open("file.txt", "r") as _f:
    myfile = _f.readlines()

myline = myfile[0]

print '\n'.join(myline[1:-1].split(','))

If you have several similar lines on your file, on can iterate with a for statement on 'myfile'.

for line in myfile:
    print '\n'.join(line[1:-1].split(','))

Note, if you are sure that brackets are on beginning and end of the line, you can use :

print "\n".join(line.strip('[]').split(','))