从字典中删除其键是列表元素的所有元素

Question

如何从字典中删除其键是列表元素的所有元素？

Answer 1

[ Note : This is not direct answer but given earlier speculation that the question looks like homework. I wanted to provide help that will help solving the problem while learning from it]

Decompose your problem which is :

1. How to get a element from a list
2. How to delete a key:value in dictionary

Further help:

How do get all element of a list on python?

For loop works on all sequences and list is a sequence.

for key in sequence: print key

How do you delete a element in dictionary?

use the del(key) method.

• http://docs.python.org/release/2.5.2/lib/typesmapping.html

You should be able to combine the two tasks.

Answer 2

for key in list_:
    if key in dict_:
        del dict_[key]

Answer 3

map(dictionary.__delitem__, lst)

Answer 4

newdict = dict(
    (key, value) 
    for key, value in olddict.iteritems() 
    if key not in set(list_of_keys)
)

---

Later (like in late 2012):

keys = set(list_of_keys)
newdict =  dict(
    (key, value) 
    for key, value in olddict.iteritems() 
    if key not in keys
)

Or if you use a 2.7+ python dictionary comprehension:

keys = set(list_of_keys)
newdict =  {
    key: value
    for key, value in olddict.iteritems() 
    if key not in keys
}

Or maybe even a python 2.7 dictionary comprehension plus a set intersection on the keys:

required_keys = set(olddict.keys()) - set(list_of_keys)
return {key: olddict[key] for key in required_keys}

---

Oh yeah, the problem might well have been that I had the condition reversed for calculating the keys required.

Answer 5

d = {'one':1, 'two':2, 'three':3, 'four':4}
l = ['zero', 'two', 'four', 'five']
for k in frozenset(l) & frozenset(d):
    del d[k]

Answer 6

for i in lst:
    if i in d.keys():
        del(d[i])

Answer 7

我对Python一无所知，但是我想您可以遍历列表并通过字典中的键删除条目吗？