Java：在新行的开头匹配重复字符，并用相同数量的替代字符替换

Question

I have a plain text file with a number of lines (new line character is \\n ) Some of these lines start with a varying number of sequential repeating whitespace characters \\\\s . I want to replace each \\\\s with   . Example file:

This is a line with no white space at the beginning
  This is a line with 2 whitespace characters at the beginning
    This is a line with 4 whitespace at the beginning

transforms to:

This is a line with no white space at the beginning
  This is a line with two whitespace characters at the beginning
    This is a line with 4 whitespace at the beginning

Any suggestions?

Thanks

Answer 1

text = text.replaceAll("(?m)(?:^|\\G) ", " ");

^ in MULTILINE mode matches the beginning of a line.
\\G matches the spot where the previous match ended (or the beginning of the input if there is no previous match).

If you're processing one line at a time, you can shorten the regex to "\\\\G " .

Answer 2

//try this:

BufferedReader reader = new BufferedReader(new FileReader("filename"));
String line;
StringBuffer buffer;
while ((line = reader.readLine()) != null) {
  buffer = new StringBuffer();
  int index = line.indexOf(line.trim());
  for (int i = 0; i < index; i++) {
    buffer.append("&nbsp;");
  }

  buffer.append(line.subString(index) + "\n"); 
  System.out.println(buffer.toString()); 
} 
reader.close();

//some more cleanup code here

Answer 3

String line;
StringBuilder buf = new StringBuilder();
int i;
for (i=0; i<line.length(); i++)
{
    if (line.charAt(i) == ' ')
        buf.append("&nbsp;");
    else
        break;
}
if (i < line.length()) buf.append(line.substr(i));
line = buf.toString();