Diagnostics.Process - 转储输出到文件

Question

Hi I need to write the result of a mysqldump to a file with a standard windows commands.

System.Diagnostics.Process proc = new System.Diagnostics.Process();
proc.EnableRaisingEvents = false;
proc.StartInfo.WorkingDirectory = "sample directory";
proc.StartInfo.FileName = "mysqldump";
proc.StartInfo.Arguments = "-u root -pPassword --all-databases > db.sql";
proc.StartInfo.RedirectStandardOutput = false;
proc.StartInfo.UseShellExecute = false;
proc.Start();
proc.WaitForExit();

But it doesn't write to file this way... I don't want to read the output and then write it to file, since mysqldump output can become really big... Any solutions?

Answer 1

Try executing through cmd.exe and enquote the command to keep your program from gobbling up the redirect:

proc.StartInfo.FileName = "cmd.exe";
proc.startinfo.Arguments = 
    "/c \"mysqldump -u root -pPassword --all-databases\" > db.sql"

Answer 2

If it's a lot of output you can use the proc.OutputDataReceived event, in the event handler just write the output to your file.

Read the MSDN article here

Answer 3

Pretty much on similar lines, but written in VB.NET. Convert it and you should be good... http://blogs.msdn.com/b/rahulso/archive/2006/04/01/run-a-command-from-the-command-prompt-and-get-its-output-in-a-windows-application.aspx

Answer 4

For piped output you may need ShellExecute to be true . If that doesnt work, you may had to pipe it yourself (ie either handle the data events, or have an async read/write loop), but the size shouldn't matter since you should only be reading small chunks of it at any time.