在构造函数初始化列表中调用函数是否可以？

Question

My gut feeling is it is not. I am in the following situation:

class PluginLoader
{
   public:
      Builder* const p_Builder;
      Logger* const p_Logger;

      //Others
};

PluginLoader::PluginLoader(Builder* const pBuilder)
   :p_Builder(pBuilder), p_Logger(pBuilder->GetLogger())
{
   //Stuff
}

Or should I change the constructor and pass a Logger* const from where PluginLoader is constructed?

Answer 1

That's perfectly fine and normal. p_Builder was initialized before it.

Answer 2

What you have is fine. However, I just want to warn you to be careful not to do this : (GMan alluded to this, I just wanted to make it perfectly clear)

class PluginLoader
{
   public:
      Logger* const p_Logger;   // p_Logger is listed first before p_Builder
      Builder* const p_Builder;

      //Others
};

PluginLoader::PluginLoader(Builder* const pBuilder)
   :p_Builder(pBuilder),
    p_Logger(p_Builder->GetLogger())   // Though listed 2nd, it is called first.
                                       // This wouldn't be a problem if pBuilder 
                                       // was used instead of p_Builder
{
   //Stuff
}

Note that I made 2 changes to your code. First, in the class definition, I declared p_Logger before p_Builder. Second, I used the member p_Builder to initialize p_Logger, instead of the parameter.

Either one of these changes would be fine, but together they introduce a bug, because p_Logger is initialized first, and you use the uninitialized p_Builder to initialize it.

Just always remember that the members are initialized in the order they appear in the class definition. And the order you put them in your initialization list is irrelevant.

Answer 3

Perfectly good practice.

I would suggest this (but its on a purely personal level):

instead of having functions called in your constructor, to group them in a init function, only for flexibility purposes: if you later have to create other constructors.