从字符串中提取数字的正则表达式

Question

Can somebody help me construct this regular expression, please...

Given the following strings...

• "April ( 123 widgets less 456 sprockets )"
• "May (789 widgets less 012 sprockets)"

I need a regular expression that will extract the two numbers from the text. The month name will vary. The brackets, "widgets less" and "sprockets" text are not expected to change between strings, however, it would be really useful if this text was able to be varied as well.

Answer 1

如果您确定只有 2 个地方有您的字符串中的数字列表，并且这是您要提取的唯一内容，那么您应该可以简单地使用

\d+

Answer 2

^\s*(\w+)\s*\(\s*(\d+)\D+(\d+)\D+\)\s*$

should work. After the match, backreference 1 will contain the month, backreference 2 will contain the first number and backreference 3 the second number.

Explanation:

^     # start of string
\s*   # optional whitespace
(\w+) # one or more alphanumeric characters, capture the match
\s*   # optional whitespace
\(    # a (
\s*   # optional whitespace
(\d+) # a number, capture the match
\D+   # one or more non-digits
(\d+) # a number, capture the match
\D+   # one or more non-digits
\)    # a )
\s*   # optional whitespace
$     # end of string

Answer 3

you could use something like:

[^0-9]+([0-9]+)[^0-9]+([0-9]+).+

Then get the first and second capture groups.

Answer 4

we can use \\b as a word boundary and then; \\b\\d+\\b

Answer 5

On bigquery you need to make sure to use the 'r' preceding the expression:

REGEXP_EXTRACT(my_string,r'\d+')

This will extract all digits from a string column.