从SQL查询中排除两个变量

Question

I know this is going to be answered in all of two seconds, but I can't find it anywhere online. I need to omit two things from my query...

1. Where display=no
2. Where verified=null

I don't want their information showing up if they've set their display to "no" or they haven't been verified (I put in a "yes" when they've been verified")

As you can see, I only included those with display='yes'. How do I get the other part?

$query = "SELECT * FROM $table WHERE display='yes'"

Do I just do this?

SELECT * FROM $table WHERE display='yes' AND verified='yes'"

Answer 1

WHERE display<>'no' AND verified IS NOT NULL

verified = NULL will never match, as by definition the result is NULL which is in effect a nomatch. Testing NULL for equality really ought to be a syntax error.

Answer 2

Thanks for the comments everyone. This is what I ended up going with:

$query = "SELECT * FROM $table WHERE display='yes' AND verified='yes'";
$result = mysql_query($query);
    if (!$result) {

    die('Invalid query: ' . mysql_error());

Worked like a charm! Excluding those who said "yes" to "please display my info" and "yes" to those that had been verified. Sorry for the confusion in my initial question!

Answer 3

Yes, you should use the AND keyword in the WHERE clause. You should also give it a try, and let us know if there are any issues.

Answer 4

尝试一下“喜欢”：

SELECT * FROM $TABLE WHERE DISPLAY LIKE 'yes' AND VERIFIED LIKE 'yes'