您如何从电话号码中检索ID？

Question

I am trying to retrieve Phone Number hence using

String addrWhere = Contacts.Phones.NUMBER + " = " + userNumber;
  String id = "";
  Cursor c = mContext.getContentResolver().query(
    Contacts.Phones.CONTENT_URI,
    new String[] { Contacts.Phones._ID }, addrWhere, null, null);
  try {
   if (c.getCount() > 0) {
    c.moveToFirst();
    id = c.getString(0);
    Log.i("IDS", id);
   }
  } finally {
   c.close();
  }
  return id;

Can anyone let me know my mistake in this?

Answer 1

Try the solution to How to query ContactsContract.CommonDataKinds.Phone on Android? which is usage of ContactsContract.PhoneLookup provider:

Uri uri = Uri.withAppendedPath(PhoneLookup.CONTENT_FILTER_URI, Uri.encode(phoneNumber));
resolver.query(uri, new String[]{PhoneLookup.DISPLAY_NAME,...

Answer 2

HI Every one... thanks for reply!!! @ Sotapanna well i found the answer as pointed by Sotapanna

pasting the working code for anyone who needs it!

private String findID(String userNumber) {
        Uri uri = Uri.withAppendedPath(PhoneLookup.CONTENT_FILTER_URI, Uri
                .encode(userNumber));
        int id = 0;
        String[] returnVals = new String[] { PhoneLookup._ID };
        Cursor pCur = mContext.getContentResolver().query(uri, returnVals,
                PhoneLookup.NUMBER + " = \"" + userNumber + "\"", null, null);
        if (pCur.getCount() > 0) {
            pCur.moveToFirst();
            id = pCur.getColumnCount();
            if (id >= 0) {
                id = pCur.getInt(0);
            }
        }

        Log.i("Contacts", "" + id);
        return String.valueOf(id);
    }