使用C＃中的LinkLabel超链接电子邮件地址

Question

我做了一个关于框的意思是允许用户点击超链接电子邮件地址，这将把他们带到Microsoft Outlook，以便能够向电子邮件地址发送电子邮件，但我不知道如何将其链接到Outlook并允许用户单击链接以执行此操作

Answer 1

You are not saying whether you are using Win- or WebForms...in WinForms I think you need to create an event-handler for the click event. Inside that you can start the default mail application by typing:

System.Diagnostics.Process.Start("mailto:youremail@xx.com");

Answer 2

Check this SO thread:

How to send email using default email client?

Basically, the click event would be something like this:

private void linkLabel1_LinkClicked(object sender,System.Windows.Forms.LinkLabelLinkClickedEventArgs e)
{
 System.Diagnostics.Process proc = new System.Diagnostics.Process();
    proc.StartInfo.FileName = "mailto:someone@somewhere.com?subject=hello&body=love my body";
    proc.Start();
}

Answer 3

Add a LinkLabel like this in the form's constructor:

linkLabel1.Links.Add(new LinkLabel.Link(0, linkLabel1.Text.Length, "mailto:bob@someaddress.com"));

Then, in the LinkLabel 's click handler:

linkLabel1.Links[linkLabel1.Links.IndexOf(e.Link)].Visited = true;
string target = e.Link.LinkData as string;
System.Diagnostics.Process.Start(target);

Answer 4

<a href="mailto:bob@someaddress.com"></a>.

If outlook is installed on the user's machine it will use it.

Edit: oops just noticed you wanted Winforms not web.

For winforms use System.Diagnositcs.Process.Start(outlook.exe /c ipm.note /m bob@someadress.com) in the click event handler.

Answer 5

Put a link label on your form.

Double-click the link-label to create your on click handler then put the system process call in it like this:

private void linkLabel1_LinkClicked(object sender, LinkLabelLinkClickedEventArgs e)
{
    linkLabel1.LinkVisited = true;
    System.Diagnostics.Process.Start("mailto:info@cybersprocket.com");
}

That will fire off the default email application that the user has configured on their windows box.

Replace the mailto: with a HTTP reference to open a web page in their default browser:

private void linkLabel1_LinkClicked(object sender, LinkLabelLinkClickedEventArgs e)
{
    linkLabel1.LinkVisited = true;
    System.Diagnostics.Process.Start("http://www.cybersprocket.com");
}