如何在PHP MYSQL中将数据库表和每条记录从一个数据库服务器复制到另一个数据库服务器？>

Question

Hi I have write a code that can copy database table from one sever to another but the record of each table did not copy how to write a function that can copy tables and each record from one db server to another?

here's my sample code:

<?php
$dbNewDB = 'newdb';
$dbNewUser = 'newroot';
$dbNewUserPswd = 'newpass';

$dbConnect = mysql_connect('localhost', 'root', 'mypassword') or die('Couldn\'t connect to MySql:'.mysql_error());
$dbNewConnect = mysql_connect('localhost', $dbNewUser, $dbNewUserPswd) or die('Couldn\'t connect to MySql:'.mysql_error());

$sqlStatement = "SHOW TABLES FROM olddb";
$result = mysql_query($sqlStatement,$dbConnect) or die('Unable to get tables: '.mysql_error());
while($row = mysql_fetch_row($result)) 
    {
        //Drop table if exist
        $sqlStatement = "DROP TABLE IF EXISTS " . $dbNewDB . "." . $row[0];
        mysql_query($sqlStatement,$dbNewConnect) or die("Failed to delete: " . mysql_error());
        //Create new table
        $sqlStatement = "CREATE TABLE " . $dbNewDB . "." . $row[0] . " LIKE olddb." . $row[0];
        echo "$sqlStatement [" . __METHOD__ . "]"; 
        mysql_query($sqlStatement,$dbNewConnect)or die("Failed to create: ". mysql_error());
        //Insert data
        $sqlStatement = "INSERT INTO " . $dbNewDB . "." . $row[0] . " SELECT * FROM " . $dbNewDB . "." . $row[0];
        echo "$sqlStatement [" . __METHOD__ . "]"; 
        mysql_query($sqlStatement,$dbNewConnect)or die("Table copy failed: ".mysql_error());
        echo "$row[0] copy done. [" . __METHOD__ . "]"; 
    }

mysql_free_result($result);
mysql_close($dbConnect);
mysql_close($dbNewConnect);

?> 

my code is already functional All i want to fixed to copy the records of each tables. Any idea?or help?

Thank you!

Answer 1

You can dump the whole database in SQL format like this:

mysqldump --user=root --password=whatever --databases dbtest --opt --quote-names --complete-insert > testbkup.sql

Then you can import it back like this:

mysql -u root -p whatever dbtest < testbkup.sql

(Note: user = root, password = whatever, dbtest is your database.)

Just saying.

Answer 2

I found these script working, you can try these:

<?php
$connect2 = mysql_connect("localhost", "root", "");
$database1 = "test1"; // destination database
mysql_select_db($database1, $connect2);
set_time_limit(0);

$database = 'dev_loribonn'; //original database
$connect = mysql_connect("localhost", "root", "");

mysql_select_db($database, $connect);

$tables = mysql_query("SHOW TABLES FROM $database");

while ($line = mysql_fetch_row($tables)) {
    $tab = $line[0];
    mysql_query("DROP TABLE IF EXISTS $database1.$tab");
    mysql_query("CREATE TABLE $database1.$tab LIKE $database.$tab") or die(mysql_error());
    mysql_query("INSERT INTO $database1.$tab SELECT * FROM $database.$tab");
    echo "Table: <b>" . $line[0] . " </b>Done<br>";
}
?>

Answer 3

A side note, if you're just copying the entire table from one database to another, you can do it all in one sql query.

 CREATE TABLE `backup_db.backup_table` SELECT * FROM `live_db.live_table`; 

I've used something similar for a backup but I dumped the entire db to a backup db

Edit: Woops, didn't see the multiple db connections.

Answer 4

Your insert statement looks off. Trying to insert into $dbNewDB with your values coming from dbNewDB. You have to turn to the old database. Below I am building two stings for the insert. $string1 = '(col1name, col2name...,)' $string2 = '(val1-1, val1-2, ...), (val2-1, val2-2,...), ...' for "INSERT INTO table $string1 VALUES $string2"

    //Insert data 

    $sql2 = "SELECT * FROM " . $row[0];
    $r = mysql_query($sql, $bConnect);
    $string1 = '('; $arr = array();
    while ($irow = mysql_fetch_assoc($r)) {$arr[] = $irow;}
    foreach($irow as $k=>$v)
    {
         $string1 .= "$k,";
    }
    $string1 = substr($string1, 0, -1) //lose last comma
    $string1 .= ')';
    $string2 = array_reduce($f, $arr); 
    $string2 = substr($string2, 0, -1) //lose last comma


    $sqlStatement = "INSERT INTO " . $dbNewDB . "." . $row[0] . " $string1 VALUES $string2";
    echo "$sqlStatement [" . __METHOD__ . "]";  
    mysql_query($sqlStatement,$dbNewConnect)or die("Table copy failed: ".mysql_error()); 
    echo "$row[0] copy done. [" . __METHOD__ . "]";  

declare $f elsewhere

$f = function($b, $x) {$a = ' ('; foreach($x as $v) {$a .= "'$v',";} $a = substr($a, 0, -1); $a .= ')'; return "$b $a,";}

Answer 5

您可以使用sql yog将表传输到不同的主机，而无需在php中编写代码。