将struct in_addr转换为文本

Question

只是想知道我是否有一个结构in_addr，如何将其转换回主机名？

Answer 1

You can use getnameinfo() by wrapping your struct in_addr in a struct sockaddr_in :

int get_host(struct in_addr addr, char *host, size_t hostlen)
{
    struct sockaddr_in sa = { .sin_family = AF_INET, .sin_addr = my_in_addr };

    return getnameinfo(&sa, sizeof sa, host, hostlen, 0, 0, 0);
}

Answer 2

Modern code should not use struct in_addr directly, but rather sockaddr_in . Even better would be to never directly create or access any kind of sockaddr structures at all, and do everything through the getaddrinfo and getnameinfo library calls. For example, to lookup a hostname or text-form ip address:

struct addrinfo *ai;
if (getaddrinfo("8.8.8.8", 0, 0, &ai)) < 0) goto error;

And to get the name (or text-form ip address if it does not reverse-resolve) of an address:

if (getnameinfo(ai.ai_addr, ai.ai_addrlen, buf, sizeof buf, 0, 0, 0) < 0) goto error;

The only other time I can think of when you might need any sockaddr type structures is when using getpeername or getsockname on a socket, or recvfrom . Here you should use sockaddr_storage unless you know the address family a priori.

I give this advice for 3 reasons:

1. It's a lot easier doing all of your string-to-address-and-back conversion with these two functions than writing all the cases (to handle lookup failures and trying to parse the address as an ip, etc.) separately.
2. Coding this way makes it trivial to support IPv6 (and potentially other non-IPv4) protocols.
3. The old functions gethostbyname and gethostbyaddr were actually removed from the latest version of POSIX because they were considered so obsolete/deprecated/broken.