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在 C# (CSV) 中将字符串转换为字节数组

[英]Converting string to byte array in C# (CSV)

I wrote a function to convert byte[] to string , and I add ";"我写了一个函数将byte[]转换为string ,并添加“;” after each byte.在每个字节之后。 Now I want to convert this string to byte[] by splitting the string (similar to a CSV string).现在我想通过拆分字符串(类似于 CSV 字符串)将此string转换为byte[]

public string ByteArrayToString(byte[] byteArray,string s)
{       
    for (int i = 0; i < byteArray.Length; i++)
    {
        s += byteArray[i].ToString() + ";";
    }
    s = s.Substring(0, s.Length - 1);
    return s;
}

How could I write a function to convert this string to that byte array again?我怎么能写一个函数来再次将此字符串转换为该字节数组?

try this尝试这个

var byteArray = new byte[] {123, 11, 111};
var stringBytes = string.Join(";", byteArray.Select(b => b.ToString()));
var newByteArray = stringBytes.Split(';').Select(s => byte.Parse(s)).ToArray();

考虑使用拆分字符串

StringBuilder will be useful instead of String (Performance wise). StringBuilder将代替String有用(性能方面)。

With StringBuilder :使用StringBuilder

byte[] buffer = System.Text.Encoding.UTF8.GetBytes(objStringBuilder.ToString());

with String :String

byte[] buffer = System.Text.Encoding.UTF8.GetBytes(objString);

I guess that you want to get rid of the ;我猜你想摆脱; when converting also.转换时也。 I think you want to do something like this:我想你想做这样的事情:

byte[] result = Encoding.UTF8.GetBytes(s.Replace(";",""));

This will fail if the original byte array actually contains a ;如果原始字节数组实际上包含一个;这将失败; that is valid data, but in that case you will have lots of problems anyway since your "CSV" file will be wrongly formatted.这是有效数据,但在这种情况下,无论如何您都会遇到很多问题,因为您的“CSV”文件格式错误。

str.Split(new char[]{';'}, 
          StringSplitOptions.RemoveEmptyEntries).Select(s => byte.Parse(s)).ToArray();
System.Text.UTF8Encoding encoding = new System.Text.UTF8Encoding();
return encoding.GetBytes(yourStringVariable);

I know you already know the answer by now... but this code solves the problem, i hope it helps someone else.我知道你现在已经知道答案了……但是这段代码解决了这个问题,我希望它可以帮助别人。

        int counter= 0;
        string cadena = "8,5,6,3,4,6,3"
        string[] foto = cadena.Split(',');
        byte[] fotoFinal = new byte[foto.Length];
        foreach (string s in foto)
        {
            fotoFinal[contador] = Convert.ToByte(s);
            counter++;
        }
string[] sbytes   = sl.Split(',');
                    byte[] b          = new byte[sbytes.Length];
                    for (int j = 0; j < sbytes.Length; j++)
                    {
                        byte newByte  = byte.Parse(sbytes[j], System.Globalization.NumberStyles.HexNumber);
                        b[j]          = newByte;
                    }

I like using number styles hex number.我喜欢使用数字样式十六进制数字。

Simply :)简单地 :)

public static byte[] Bytes ( this string Key )
{
    return Enumerable.Range(0, Key.Binary().Length / 8 )
                     .Select(Index => Convert.ToByte(
                         Key.Binary().Substring(Index * 8, 8), 2))
                     .ToArray();
}

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