[英]How do I pass variable inside find and bash -c?
I have issues with passing variable to %exe part of the code.我在将变量传递给代码的 %exe 部分时遇到问题。
Here is my working code that I use inside bash script:这是我在 bash 脚本中使用的工作代码:
## Function
targz() {
find $1 -type f -name "*.$2" -exec \
bash -c 'old=$(basename {}); new=${old/%exe/tar\.gz}; \
tar -zcvf $new $old; ' \;
}
## Function Call
## targz [directory] [extension]
targz . 'exe';
and yes I've tried using it some thing like this:是的,我试过用它来做这样的事情:
new=${old/%$2/tar\.gz};
but it generates filenames like: file.exetar.gz .但它生成的文件名如: file.exetar.gz 。
Try:尝试:
targz() {
find $1 -type f -name "*.$2" -exec \
bash -c 'old=$(basename {}); new=${old/'"$2"'/tar\.gz}; \
tar -zcvf $new $old; ' \;
}
The trick is to get out of the single quote, so that variable expansion will be performed.诀窍是摆脱单引号,以便执行变量扩展。
Use env
to set an environment variable for bash
:使用env
为bash
设置环境变量:
targz() {
find "$1" -type f -name "*.$2" -exec \
env ext="$2" bash -c 'old=$(basename "{}"); new=${old/%$ext/tar\.gz}; \
tar -zcvf "$new" "$old"; ' \;
}
I added some quoting to protect against spaces in filenames.我添加了一些引用以防止文件名中出现空格。
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