如何将十六进制的字符串表示形式转换为c中的十六进制值？

Question

If I have

char input[50] = "xFFFF";
int a;

How can I store the numerical value of input in a? the language is C.

Answer 1

One way to do it might be:

if (sscanf(input, "x%x", &a) == 0) {
    /* matching failed */
}

If your input uses a real hex specifier (like "0xFFFF") you can just use %i:

if (sscanf(input, "%i", &a) == 0) {
    /* matching failed */
}

Answer 2

You can use strtol function

char *ptr;
long a = strtol( input, &ptr, 16 );

Answer 3

One way:

#include <stdlib.h>

int main()
{
   char *p="xFFFF";
   long lng=strtol(&p[1], (char **)0, 16);
   printf("%ld\n", lng);
   return 0;
}

Answer 4

请参阅C ++将十六进制字符串转换为有符号整数 ，如果您在纯C环境中，请确保向下滚动。