C ++ / Arduino：如何将字符串/字符串数组转换为字节？

Question

I want to convert

char lineOneC[8] = {0,1,1,0,0,0,0,1}; 

into

byte lineOneB = B01100001;

How do I do this in C++ / Arduino?

Answer 1

I'm not sure about specific restrictions imposed by the Adruino platform, but this should work on any standard compiler.

char GetBitArrayAsByte(const char inputArray[8])
{
    char result = 0;
    for (int idx = 0; idx < 8; ++idx)
    {
        result |= (inputArray[7-idx] << idx);
    }
    return result;
}

A test of this code is now on Codepad , if that helps.

Answer 2

Just shift 0 or 1 to its position in binary format. Like this

char lineOneC[8] = {0,1,1,0,0,0,0,1}; 
char lineOneB = 0;
for(int i=0; i<8;i++)
{
    lineOneB |= lineOneC[i] << (7-i);
}

Answer 3

char lineOneC[8] = { 0, 1, 1, 0, 0, 0, 0, 1 };
unsigned char b = 0;

for ( int i = 7; i >= 0; i-- ) {
    b |= lineOneC[i] << ( 7 - i );
}

Answer 4

If you know that the values of your character array will always be either 1 or 0:

char line[8] = { '0', '1', '1', '0', '0', '0', '0', '1'};

unsigned char linebyte = 0;
for (int i = 7, j = 0; j < 8; --i, ++j)
{
    if (line[j] == '1')
    {
        linebyte |= (1 << i);
    }
}

Answer 5

If the result is supposed to be B01100001 , then byte 0 is the MSB (most significant bit), not byte 7 ...

char line[8] = { 0, 1, 1, 0, 0, 0, 0, 1 };
unsigned char b = 0;
for ( int ii = 0; ii < 8; ii++ )
{
  b <<= 1;
  b |= line[ii];
}

The other answers I've seen, if I read them correctly, put the MSB on byte 7.

EDIT: Fixed quotes; miscopied it before.