简体   繁体   English

MySQL Where子句错误

[英]MySQL Where Clause error

i have the following statement 我有以下声明

$result = mysql_query("SELECT * from rests ORDER BY name asc WHERE flag = '1' LIMIT 0 , 20");

am getting the following error 正在收到以下错误

Invalid query: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE flag = '1' LIMIT 0 , 20' at line 1

am not sure where am going wrong :( 不知道哪里出了问题:(

$result = mysql_query("SELECT * from rests  WHERE flag = '1' ORDER BY name asc LIMIT 0 , 20");

You cannot have the ORDER BY clause before WHERE clause. 您不能在WHERE子句之前有ORDER BY子句。

Refer to the MySQL select syntax for the correct order of various clauses. 有关各种子句的正确顺序,请参考MySQL select语法

Try this: 尝试这个:

SELECT * from rests WHERE flag = '1' ORDER BY name asc LIMIT 0 , 20

Also Ordering in ascending is default, you may drop the asc . 同样,默认asc ,您可以删除asc

The ORDER BY clause must be after the WHERE clause. ORDER BY子句必须在WHERE子句之后。 That's all it is. 仅此而已。

ORDER BYWHERELIMIT之后。

WHERE之前去ORDER BY

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM