PHP字符串/日期替换正则表达式

Question

I have string in following format 07_Dec_2010, I need to convert it to 07 Dec, 2010

How can I achieve following using single statement

Answer 1

If you are using PHP 5.3, you could also use the following to a) parse the date string and b) format it however you like:

$formatted = date_create_from_format('d_M_Y', '07_Dec_2010')->format('d M, Y');

^{( date_create_from_format() could also be DateTime::createFromFormat() )}

If you're not using 5.3 yet, you can use the following a) convert your string into a format that strtotime() understands, then b) format it however you like:

$formatted = date('d M, Y', strtotime(str_replace('_', '-', '07_Dec_2010')));

All that said, the other answers are fine if you just want to move portions of the string around.

Answer 2

You can do it using explode function as:

$dt = '07_Dec_2010';

list($d,$m,$y) = explode('_',$dt);    // split on underscore.
$dt_new = $d.' '.$m.','.$y;           // glue the pieces.

You can also do it using a single call to preg_replace as:

$dt_new = preg_replace(array('/_/','/_/'),array(' ',','),$dt,1);

Or also as:

$dt_new = preg_replace('/^([^_]*)_([^_]*)_(.*)$/',"$1 $2,$3",$dt);

Ideone link

Answer 3

$new_date = preg_replace('/(\d+)_(\w+)_(\d+)/', '${1} ${2}, ${3}', $date);

随意安排$ {1}，$ {2}，$ {3}