[英]SimpleDateFormat fails to reject input missing century on the year of the input, despite “yyyy” in the formatting pattern
I have a SimpleDateFormat with the pattern yyyy-Md"
, and the following scenario: 我有一个模式为
yyyy-Md"
的SimpleDateFormat,并且具有以下情形:
String str = "02-03-04";
SimpleDateFormat f = new SimpleDateFormat("yyyy-M-d");
f.setLenient(false);
System.out.println(f.parse(str));
The output is Sat Mar 04 00:00:00 EST 2
输出为
Sat Mar 04 00:00:00 EST 2
My goal was to only catch dates in the format like 2004-02-03 and to ignore 02-03-04. 我的目标是只捕获格式为2004-02-03的日期,而忽略02-03-04。 I thought the yyyy in the pattern would require a 4 digit year, but clearly this is not the case.
我认为格式中的yyyy需要4位数字的年份,但显然不是这样。 Can anyone explain why this is not throwing a parse exception?
谁能解释为什么这没有引发解析异常? I would like it to...
我想要...
Well, I can explain it from the docs : 好吧,我可以从docs中解释一下:
For parsing, if the number of pattern letters is more than 2, the year is interpreted literally, regardless of the number of digits.
对于解析,如果模式字母的数量大于2,则将按字面意义解释年份,而不考虑数字的数量。 So using the pattern "MM/dd/yyyy", "01/11/12" parses to Jan 11, 12 AD
因此,使用模式“ MM / dd / yyyy”,“ 01/11/12”将解析为公元12月11日
It's possible that Joda Time would be stricter - and it's a better API in general, IMO... Joda Time可能会更严格-IMO总体而言是更好的API ...
You could always throw an exception if the year is less than 1000 after parsing... 如果解析后的年份少于1000年,您总是可以抛出异常。
Using java.time , that input with that formatting pattern fails, just as you expected. 如您所料,使用java.time时 ,使用该格式模式的输入失败。
LocalDate
.parse(
"02-03-04" ,
DateTimeFormatter.ofPattern ( "uuuu-M-d" )
)
…throws java.time.format.DateTimeParseException
…引发
java.time.format.DateTimeParseException
The classes you were using are now supplanted by the modern java.time classes defined in JSR 310 and built into Java 8 and later. 现在,您所使用的类已由 JSR 310中定义并内置于Java 8及更高版本中的现代java.time类所取代。
The LocalDate
class represents a date-only value without time-of-day and without time zone or offset-from-UTC . LocalDate
类表示仅包含日期的值,没有日期, 时间段或offset-from-UTC 。
Define a custom formatting pattern as you asked. 根据要求定义自定义格式设置模式。 Use the
DateTimeFormatter
class. 使用
DateTimeFormatter
类。
DateTimeFormatter f = DateTimeFormatter.ofPattern ( "uuuu-M-d" );
Try to parse your input. 尝试解析您的输入。
String input = "02-03-04";
LocalDate localDate = LocalDate.parse ( input , f );
We encounter a DateTimeParseException
, failing on the missing century of the year of the input. 我们遇到了
DateTimeParseException
,在缺少输入年份的世纪失败。 Just as you expected. 如您所料。
Exception in thread "main" java.time.format.DateTimeParseException: Text '02-03-04' could not be parsed at index 0
线程“主”中的异常java.time.format.DateTimeParseException:无法在索引0处解析文本“ 02-03-04”
The java.time framework is built into Java 8 and later. java.time框架内置于Java 8及更高版本中。 These classes supplant the troublesome old legacy date-time classes such as
java.util.Date
, Calendar
, & SimpleDateFormat
. 这些类取代了麻烦的旧的旧式日期时间类,例如
java.util.Date
, Calendar
和SimpleDateFormat
。
To learn more, see the Oracle Tutorial . 要了解更多信息,请参见Oracle教程 。 And search Stack Overflow for many examples and explanations.
并在Stack Overflow中搜索许多示例和说明。 Specification is JSR 310 .
规格为JSR 310 。
The Joda-Time project, now in maintenance mode , advises migration to the java.time classes. 现在处于维护模式的Joda-Time项目建议迁移到java.time类。
You may exchange java.time objects directly with your database. 您可以直接与数据库交换java.time对象。 Use a JDBC driver compliant with JDBC 4.2 or later.
使用与JDBC 4.2或更高版本兼容的JDBC驱动程序 。 No need for strings, no need for
java.sql.*
classes. 不需要字符串,不需要
java.sql.*
类。
Where to obtain the java.time classes? 在哪里获取java.time类?
The ThreeTen-Extra project extends java.time with additional classes. ThreeTen-Extra项目使用其他类扩展了java.time。 This project is a proving ground for possible future additions to java.time.
该项目为将来可能在java.time中添加内容提供了一个试验场。 You may find some useful classes here such as
Interval
, YearWeek
, YearQuarter
, and more . 您可以在这里找到一些有用的类,比如
Interval
, YearWeek
, YearQuarter
,和更多 。
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