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如何保证ThreadPoolExecutor中的FIFO执行顺序

[英]How to guarantee FIFO execution order in a ThreadPoolExecutor

I create a ThreadPoolExecutor with this line of code : 我用这行代码创建一个ThreadPoolExecutor:

private ExecutorService executor = new ThreadPoolExecutor(5, 10, 120, TimeUnit.SECONDS, new ArrayBlockingQueue<Runnable>(20, true));

Then, I run 25 tasks (T01 to T25) so the situation is : 然后,我运行25个任务(T01到T25),所以情况是:

  • 5 tasks currently running (T01 to T05) 当前正在运行的5个任务(T01到T05)
  • 20 tasks waiting in the Queue (T06 to T25) 在队列中等待的20个任务(T06到T25)

When I put 1 more task (T26), as the queue is full, I expected that the older task (T06) is removed to be launched (because MaxPoolSize is not reached) and the new task (T26) is placed at the end of the queue. 当我再添加1个任务(T26)时,当队列已满时,我预计将删除旧任务(T06)以启动(因为未达到MaxPoolSize)并且新任务(T26)被放置在末尾队列。

But in real life, if Queue is full and MaxPoolSize is not reached, the newest task is started. 但在现实生活中,如果Queue已满并且未达到MaxPoolSize,则启动最新任务。

So, I have ... 所以我有 ...

  • 6 tasks currently running (T01 to T05 and T26) 当前正在运行的6个任务(T01到T05和T26)
  • 20 tasks waiting in the Queue (T06 to T25) 在队列中等待的20个任务(T06到T25)

... instead of ... ... 代替 ...

  • 6 tasks currently running (T01 to T06) 当前正在运行的6个任务(T01到T06)
  • 20 tasks waiting in the Queue (T07 to T26) 在队列中等待的20个任务(T07到T26)

Can I configure the ThreadPoolExecutor to get the expected result ? 我可以配置ThreadPoolExecutor来获得预期的结果吗? Should I use another classes ? 我应该使用其他课吗?

For information, part of ThreadPoolExecutor source code 有关信息,请参阅ThreadPoolExecutor源代码的一部分

public void execute(Runnable command) {
    if (command == null)
        throw new NullPointerException();
    if (poolSize >= corePoolSize || !addIfUnderCorePoolSize(command)) {
        if (runState == RUNNING && workQueue.offer(command)) {
            if (runState != RUNNING || poolSize == 0)
                ensureQueuedTaskHandled(command);
        }
        else if (!addIfUnderMaximumPoolSize(command))
            reject(command); // is shutdown or saturated
    }
}


private boolean addIfUnderMaximumPoolSize(Runnable firstTask) {
    Thread t = null;
    final ReentrantLock mainLock = this.mainLock;
    mainLock.lock();
    try {
        if (poolSize < maximumPoolSize && runState == RUNNING)
            t = addThread(firstTask);
    } finally {
        mainLock.unlock();
    }
    if (t == null)
        return false;
    t.start();
    return true;
}

Thanks 谢谢

I would make the core size equal the maximum. 我会让核心大小等于最大值。 This is how most of the pools are used and I am not sure when would be the downside in your case, but you would get the tasks executed in order. 这就是大多数池的使用方式,我不确定在你的情况下什么时候会出现缺点,但你会按顺序执行任务。

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